Question

1. LCM of the numbers 45 and 105 is 315. HCF of these numbers is:
(d) 105
(a) 15
(b) 30
(c) 45
2.
For any integer a and 2, there exist unique integers q and r such t​

Answer 1

Answer:

LCM × HCF = product of the 2 no.s

315 × HCF = 45 × 105

HCF = 45 × 105 /315

HCF = 15 is your required answer

Step-by-step explanation:

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