Question

1)Length and breadth of rectangular field is in ratio 3:2
If the area is 4056 sq.m, find the cost of fencing field at rate of rs. 5 per metre​

Answer 1

Step-by-step explanation:

Given that:

Length of a rectangle field =3x

Breadth of a rectangle field =2x

Area =3456 m

2

3x×2x=3456 m

2

6x

2

=3456 m

2

x

2

=576 m

2

x=24 m

Therefore, the length =72 m

Breadth =48 m

Perimeter of the rectangular field =72+48=120 m

Cost of 1 meter =Rs.4

Cost of 120 meter =Rs.4×120=Rs.480.

Answer 2

Answer:

• Rs.1300

SOLUTION:

• Let the length and breadth of a rectangular field be 3x and 2x respectively.

$\\ \bold A \bold r\bold e\bold a = \bf \: l \times b = 3x \times 2x \\ \\ \implies \bf\: 6 {x}^{2} = 4056 \\ \\ \implies \bf \: {x}^{2} = \frac{4056}{6 } \\ \\ \implies \bf \: {x}^{2} = 676 \\ \\ \therefore \bf \: {x}^{2} = {(26)}^{2} \\ \\ \therefore \bf \: x = 26 \\ \\ \\ \bf \: Therefore, \: \: \: \: \: \: Length = 3x = 3 \times 26 = 78m \\ \bf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: Breadth = 2 x = 2 \times 26 = 52m\\ \bf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: Perimeter = 2(l \times b) = 2(78 + 52) = 2 \times 130 = 260 \\ \\ \\ \bf \: 1m \: of \: fencing \: costs = \: Rs.5 \\ \bf \therefore \: 260m \: of \: fencing \: costs = 260 \times 5 = Rs.1300 \\ \\ \\ \therefore {\mathbb{ \boxed {Fencing \: the \: field \: will \: cost \: Rs.1300}}}$

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