Question

1)Length and breadth of rectangular field is in ratio 3:2
If the area is 4056 sq.m, find the cost of fencing field at rate of rs. 5 per metre​

Answer 1

RS.1300

Step-by-step explanation:

have not enough time brother.

Answer 2

$\large{\boxed{\boxed{\sf Let's \: Underst \: and \: Concept!}}}$

Here, we have give the ratio of Length and Breadth of Rectangle and area of Rectangle js 4056m² and we have ti find the cost of fencing the field at the rate of Rs.5/m. So, here f1st we let Length and Breadth if Rectangle. Thus, by using area if Rectangle which is given we can find the value of x. By the value of x we will find the Length and Breadth of Rectangle. To find cost of fencing we simply multiply 5 by its Perimeter.

$\huge{\underline{\large{\boxed{\sf AnSwer}}}}$

___________________________

Given:-

• Ratio of Length and Breadth = 3:2
• Area of Rectangle = 4056m²
• Rate of fencing = Rs.5/m

Find:-

• Cost of fencing the field.

Solution:-

Let, Length of Rectangle = 3x m

Breadth of Rectangle = 2x m

we, know that

$\underline{\large{\boxed{\sf Area \: of \: Rectangle = l \times b}}}$

$\sf where \small{\begin{cases} \sf l = 3x \: m \\ \sf b = 2x \: m \\ \sf Area = 4056 {m}^{2} \end{cases}}$

$\bigstar\textsf{Substituting these values:-}$

$\implies\sf Area \: of \: Rectangle = l \times b$

$\implies\sf 4056= 3x\times 2x$

$\implies\sf 4056= 6 {x}^{2}$

$\implies\sf \dfrac{4056}{6}= {x}^{2}$

$\implies\sf 676= {x}^{2}$

$\implies\sf \sqrt{676}= x$

$\implies\sf 26m= x$

So,

> Length of Rectangular = 3x = 3×26 = 78m

> Breadth of Rectangle = 2x = 2×26 = 52m

Now, using

$\underline{\large{\boxed{\sf Perimeter \: of \: Rectangle = 2(l + b)}}}$

$\sf where \small{\begin{cases} \sf l = 78m \\ \sf b = 52m \end{cases}}$

$\dashrightarrow\sf Perimeter \: of \: field = 2(l + b)$

$\dashrightarrow\sf Perimeter \: of \: field = 2(78 + 52)$

$\dashrightarrow\sf Perimeter \: of \: field = 2(130)$

$\dashrightarrow\sf Perimeter \: of \: field = 2 \times 130$

$\dashrightarrow\sf Perimeter \: of \: field = 260m$

Now,

→ Cost of fencing 1m of field = Rs.5

→ Cost of fencing 260m of field = 260×5 = Rs.1300

$\underline{\boxed{\sf \therefore Cost \: of \:the \: fencing \: field \: is \: Rs.1300}}$