Question

1. Let a > 0 be a real number and p and q be rational numbers. Then
ар
(i)
aP. aq= ap+q
(ii) (ap)q = apq

(iv) apbp= (ab)p
​

Answer 1

Given :  a > 0 be a real number and p and q be rational numbers.  

To Find : which one is correct

ap. aq= ap+q

(ap)q = apq

apbp= (ab)p

Solution:

ap. aq  = a.a .p.q

= a²pq

a²pq ≠ ap+q

=> ap. aq ≠ ap+q

(ap)q = apq  TRUE

apbp=  abpp

=abp²

(ab)p = abp

abp²   ≠  abp

=> apbp= (ab)p

(ap)q = apq  TRUE

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Answer 2

Answer:

Thes man is saed correct answer