Question

1. Let f be mod-11 function. Compute.
(a) f(417) (b) f(40) (C) f(-253).​

Answer 1

Answer:

C=ans

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Answer 2

(a) The value of f(417) is 10.

(b) The value of f(40) is 7.

(c) The value of f(-253) is 0.

Step-by-step explanation:

It is given that f is mod-11 function. It means

$f(x)=x(mod-11)$

If x(mod-11)=a, then a is remainder when x is divided by 11.

(a)

$f(417)=417(mod-11)$

$f(417)=10$          (If 417 is divided by 11, then remainder is 10)

The value of f(417) is 10.

(b)

$f(40)=40(mod-11)$

$f(40)=7$          (If 40 is divided by 11, then remainder is 7)

The value of f(40) is 7.

(c)

$f(-253)=-253(mod-11)$

$f(-253)=0$          (If -253 is divided by 11, then remainder is 0)

The value of f(-253) is 0.

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