Question

1. Let f(x) and g(x) be differentiable for 0≤x≤ 1, such that f(0) = 2, g(0)=0,f(1) = 6. Let there exist a real number c in [0,1] such that f'(c) = 2g'(c), then the value of g (1) must be

1 b) 2 c)-2 d)-1​

Answer 1

Correct option is B)

From lagrange's theorem