Question

1) let P(x) =x² - 4x+3. find the value
of P(0)P(1), P(2), P(3) and obtain
zeroes of the polynomial P(×)​

Answer 1

Explanation:

p(0)=0-4(0)+3=3

p(2)=(2)^2-4(2)+3=-1

p(3)=(3)^2-4(3)+3=0

so one zero of given polynomial is 3.

let take other zero=x

from the polynomial, sum of zeroes=-b/a=-(-4)

=4

so ,

x+3=4

x=1

so the other zero of given polynomial is 1.

product of zeroes of the polynomial=c/a

3×1=3

3=3

so the zeroes of the polynomial are 1,3.

hope it helps