Math, asked by miryaseenhyder1801, 6 months ago

1.
Let U= { 1, 2, 3, 4, 5, 6, 7, 8, 9 }, A = { 1, 2, 3, 4), B = { 2, 4, 6, 8 } and
C= { 3,4,5,6). Find (1) A' (ii) B' (iii) (AUC) (iv) (AUB)' (v) (A')'
(vi) (B-C)​

Answers

Answered by SuitableBoy
78

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Given :

• U = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 }

• A = { 1 , 2 , 3 , 4 }

• B = { 2 , 4 , 6 , 8 }

• C = { 3 , 4 , 5 , 6 }

To Find :

  1. A'
  2. B'
  3. A\cupC
  4. (A\cupB)'
  5. (A')'
  6. (B-C)

Solution :

1. A' or A compliment

In this , we will consider all the elements other than those present in set A.

A' = { 5 , 6 , 7 , 8 , 9 }

2. B' or B compliment

In this , we will consider all the elements other that those present in set B .

B' = { 1 , 3 , 5 , 7 , 9 }

3. \rm\bold{A \cup C}

or A union C

In this , we will take all the elements present in set A and set C (avoiding repetition).

\rm{A \cup C } = { 1 , 2 , 3 , 4 , 5 , 6 }

4. \rm\bold{(A \cup B)'}

In this , we will first take union of set A and set B ..

(A\cupB) = { 1 , 2 , 3 , 4 , 6 , 8 }

Now , we will take it compliment , means all other elements except the ones present in the union .

(A\cupB)' = { 5 , 7 , 9 }

5. (A')'

The compliment of a compliment is the same set .

(A')' = A = { 1 , 2 , 3 , 4 }

6. ( B - C )

In this , we will remove all the elements from set B which belongs to set C .

( B - C ) = { 2 , 8 }

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