Question

1. Let X=(a, e, i, o, u)and Y=(a, g, 0, f). Verify that n(A-B) = n(A) - n(AnB)​

Answer 1

Step-by-step explanation:

Answer

We know that complement of set A is

A

′

=U−A

Given U={a,b,c,d,e,f,g,h}

(i) A={a,b,c}

A

′

={d,e,f,g,h}

(ii) B={d,e,f,g}

∴B

′

={a,b,c,h}

(iii) C={a,c,e,g}

∴C

′

={b,d,f,h}

(iv) D={f,g,h,a}

∴D

′

={b,c,d,e}

Answer 2

Answer:

Step-by-step explanation:
Given that A = ( a,e,i,o,u) and B = ( a,g,o,f).
To verify n(A-B) = n(A) - n(A∩B)

So, (A-B) = (a,e,i,o,u) - ( a,g,o,f)
= (e,i,u)
(AnB) = (a,o)
A = (a,e,i,o,u)

And ,
n(A-B) = 3
n(A) = 5
n(AnB) = 2

Therefore,
n(A-B) = n(A) - n(AnB)
3 = 5 - 2
3 = 3
It's verified that LHS = RHS.

THANKS.