Question

1 liter of a gaseous hydrocarbon weighs as much as one liter of co2. Then the molecular formula of hydrocarbon is-

Answer 1

Answer: $C_3H_8$

Explanation: According to avogadro's law, 1 mole of every gas occupies 22.4 L at STP and weighs equal to the molecular mass of that substance.

Thus 22.4 L of $CO_2$ weighs 44 g.

1 L of $CO_2$ will weigh=$\frac{44}{22.4}=1.96g$

Thus 1 L of gaseous hydrocarbon must weigh 1.96 g at STP and 22.4 L of  gaseous hydrocarbon must weigh 44 g at STP.

The hydrocarbon with molecular formula $C_3H_8$ has molecular weight of 44 g and occupies 22.4 L at STP.

Answer 2

Answer:

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