1 litre of 1 m coppersulphate solution is electrolysed after passing 2 farad charge the molarity of copper sulphate will be???
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For 1 M CuSO4 soln.,
moles x valence factor = q/F
Therefore,
1 x 1 x 2 = q/F
q = 2F
Therfore for passing 2F charge would consumed the soln. completeley and hence the Molarity becomes zero perhaps!
moles x valence factor = q/F
Therefore,
1 x 1 x 2 = q/F
q = 2F
Therfore for passing 2F charge would consumed the soln. completeley and hence the Molarity becomes zero perhaps!
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