Question

1 litre of an aqueous solution of NACL contains 117g of the dissolved salt.calculate the no. of moles of the solute in the solution?

Solve fast I will mark as the brainliest

Answer 1

Answer:

Use the number of moles of sodium per mole of sodium sulfate.

Explanation:

Sodium sulfate is Na2SO4

First, calculate the moles of sodium sulfate you have in a 14.2g sample.

Find the molar mass of sodium sulfate

molar mass = atomic mass in grams

2(23) + 32 + 4(16) = 142 grams per moleDivide the mass of the sample by the molar mass to obtain moles 

14.2g142gmol−1 = 0.1 mol

Now, for every 1 mol of Na2SO4 you have 2 moles of Na+ ions. Multiple the moles of Na2SO4 that you found just then by 2 to obtain the moles of sodium ions.

Use Avogadro's number (6.022 x 1023) to find the number of ions present. (Recall that Avogrado's number is the number of particles per mole of a substance).

6.022 x 1023 x 0.2 mol = 1.2044 x 1023 ions