Question

1 litre of an aqueous solution of NaCl contains 117g of the dissolved salt. Calculate the number of moles of the solute in the solution. (Na = 23u , Cl = 35.5)
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Answer 1

Explanation:

For this we'd use the following equation:

Molarity=NV

N meaning the grams/moles and V meaning the volume in Liters.

So first we find the molar mass of NaCl to be 58.44 grams.

we can setup this proportion to find the 'n'

x117=158.44

17758.44=3.03

Now we convert the 180 mL to L, so .180 L.

Finally,

M=3.03.180

M=16.83

The molarity (mole fraction) is 16.83 Molar