Question

1 litre solution containing 490g of sulphuric acid is diluted to 10 litre with water. What is the normality of the
resulting solution?
(1)0.5N
(2) 1.0N
(3) 5.0N
(4) 10.0N
​

Answer 1

o.5 nitrogen hoga because of sulphuric acid

Answer 2

Answer: (2) 1.0 N

Explanation:- Normality of a solution is defined as the number of gram equivalents of solute dissolved per Liter of the solution.

${\text{Equivalent mass}}=\frac{\text{Molecular mass}}{{\text{Basicity of an acid}}}=\frac{98g}{2}=49g$

$Normality of} H_2SO_4=\frac{\text {given mass}}{\text {Equivalent mass}\times Volume of solution in L}=\frac{490}{49\times 1L}=10N$

According to the neutralization law,

$N_1V_1=N_2V_2$

where,

$N_1$ = Normality of first solution = 10 N

$V_1$ = volume of NaOH solution = 1 L

$N_2$ = Normality of second solution = ? N

$V_2$ = volume of second solution = 10L

$(10N)\times 1L=(N_2)\times (10L)$

$N_2=1N$

Therefore, the normality of the resultant solution will be 1N.