Question

1 litre solution containing 490gm of sulphuric acid is diluted to 10litre with water. what is the normality of the resulting solution

Answer 1

Answer:

1 N.

Explanation:

Molarity of 1 litre of 490 g of sulphuric acid = 5 M.

Molarity = (No. of moles)/(Volume of solvent in litres)

=(490/98)/1

=5 M

Normality = Molarity * Basicity of Sulphuric Acid

= 5*2 = 10 N.

When this solution is diluted to 10 litres.

Using formula.

N1V1=N2V2

10*1=N2*10

N2= 1 N