Question

1) locate √3 on the number line 2)find the values of 32^1/5 , 125^1/3 , 16^3/4​


answer the question fast plz

Answer 1

Answer:

1. First draw a number line having points (at least) [0,3]. If we denote the point 0 as “O” and point 1 as “A” then OA will be equal to 1 unit. Then at point A draw a perpendicular of length AB=1 unit ( equal to the distance from 0 to 1 in the number line i.e. OA). And join the points O and A, so that OAB is a right angled triangle. Then by pythagoras theorem,

OB^2=OA^2+AB^2

=> OB=sqrt (1^2+1^2)

=>OB = root2

Now, again draw a perpendicular at point B of length BC= 1 unit and join the points O and C. Again by pythagoras theorem we get OC = root 3. Then by compus taking radius =OC, draw an arc so that it cuts the number line at D. Then the distance OD will be the square root of 3.