Question

1/log base a power abc+1/log base b abc + 1/log base c power abc =1​

Answer 1

Step-by-step explanation:

$\frac{1}{log_a \: abc} + \frac{1}{log_b \: abc} + \frac{1}{log_c \: abc} = 1 \\ LHS \\ = \frac{1}{log_a \: abc} + \frac{1}{log_b \: abc} + \frac{1}{log_c \: abc} \\ = \frac{1}{ \frac{log \: abc}{log \: a} } + \frac{1}{ \frac{log \: abc}{log \: b} } +\frac{1}{ \frac{log \: abc}{log \: c} } \\ = \frac{log \: a}{log \: abc} + \: \frac{log \: b}{log \: abc} + \frac{log \: c}{log \: abc} \\ = \frac{log \: a + log \: b \: + log \: c}{log \: abc} \\ = \frac{log \: abc}{log \: abc} \\ = \: 1 \\ = RHS$

Answer 2

Answer:

answer is proved

Step-by-step explanation:

answer is 1

hence answer is proved