Question

1/log base x xy + 1/log basey xy​

Answer 1

Answer:

QUESTION■

1logxxy+1logyxy=?\frac{1}{ log_{x}xy } + \frac{1}{ log_{y}xy} = ?

log

x

xy

1

+

log

y

xy

1

=?

■ANSWER■

1logxxy+1logyxy=logxyx+logxyy=logxy(x×y)=logxyxy=1\begin{lgathered}\frac{1}{ log_{x}xy } + \frac{1}{ log_{y}xy} \\ = { log_{xy}x} + log_{xy}y \\ = log_{xy}(x \times y) \\ = log_{xy}xy \\ = 1\end{lgathered}

log

x

xy

1

+

log

y

xy

1

=log

xy

x+log

xy

y

=log

xy

(x×y)

=log

xy

xy

=1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

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