1+log10a=2 log10b হলে aকে bএর দ্বারা প্রকাশ করি
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Answer:
a=b^2/100
Step-by-step explanation:
1+log10a=2 log10b
log10a =2 log10b - 1
log10a=2 log10b - log10
log10a=log10b^2-log10
log10a=log(b^2/10)
10a=b^2/10
a=b^2/100
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