Question

1+logx-x÷1-2x+x^2 evaluate the answer

Answer 1

explanation:

x ->     1 + logx - x / 1 - 2x + x^2

lim    

since it is in the for of 0/0 ,so apply L-hopital's rule

-lim        (1/2) (1 - x / 2x (1 - x ))

x ->1

=> -1/2  

i hope this helps u...

please mark it as brainlist answer ❤