Question

1) Lt x=1 ( 1 + sinπx)^cotπx =?
2) Lt x=0 ( 1 + tanx)^cotx =?

need brief explanation
best answer i will Mark brainliest ✨✨❤️​

Answer 1

Step-by-step explanation:

lim

e(1+sinπx)

cotπx

=e⋅

x→1

lim

(1+sinπx)

(1/sinπx)cosπx

=e⋅e

cosπ

=e⋅e

−1

=1