Question

1] (m-1)x² -2(m-1)x +1 =0 find m , which has real and equal roots.​

Answer 1

Step-by-step explanation:

Given, real and equal roots

b^2- 4ac =0

b= -2(m-1)

a= (m-1)

c= 1

4(m-1)^2 -4 (m-1) ×1 =0

4 ( m^2-2m +1 -m +1) =0

m^2-3m +2 =0

m^2 -2m -m +2 =0

m(m-2) -1 ( m-2) =0

m=1,2