Question

1-m^2=0 what is the value of m​

Answer 1

Answer:

1......

...

...........

Answer 2

$1 - {m}^{2} = (1) {}^{2} - m {}^{2} \\ applying \: the \: identity \: a {}^{2} - {b}^{2} = (a \times + b)(a - b) \\ = (1 + m)(1 - m)$

Either

1+m = 0

=> m = -1

Or

1-m = 0

=> -m = -1

=> m = 1

Therefore values of m is 1 and -1

Hope it helps....

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