Question

(1+m)^2-(1-m)^2 factorisation plz help​

Answer 1

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${(1 + m)}^{2} - {(1 - m)}^{2} \\ \\ \\ = {1}^{2} + 2m + {m}^{2} - ( {1}^{2} - 2 m + {m}^{2} ) \\ \\ \\ = 1 + 2m + {m}^{2} - 1 + 2m - {m}^{2} \\ \\ \\ = 1 - 1 + 2m + 2m + {m}^{2} - {m}^{2} \\ \\ \\ = 4m$

• Thnku :)