Question

1 M hcl and 2M hcl are mixed in volume ratio 4:1 what is the final molarity of hcl solution

Answer 1

Given,

Concentration of HCl, c₁ = 1 M

Concentration of HCl, c₂ = 2 M

As they are mixed in the volume ratio of 4:1, so the total amount is 5.

So, amount of c₁ = $\frac{4}{5}$ × 1 M

and, amount of c₂ = $\frac{1}{5}$ × 2 M

∴ The final molarity of HCl solution

= ( $\frac{4}{5}$ × 1 M ) + ( $\frac{1}{5}$ × 2 M )

= ( $\frac{4}{5}$ + $\frac{2}{5}$ ) M

= 1.2 M