Question

1-(m+n)²
$1 -(x + y)2$
​

Answer 1

As we know that :

a²-b² = (a+b)(a-b)

(1) 1-(m+n)²

=> (1)²-(m+n)² = (1+m+n)(1-m-n)

(2) 1-(x+y)²

=> (1)²-(x+y)² = (1+x+y)(1-x-y)

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Answer 2

Step-by-step explanation:

$1 - (m + n) { }^{2} \\ 1 { }^{2} - (m + n) ^{2} \\ 1 - (m + n)...1 + (m + n)$

$1 - (x + y) {}^{2} \\ 1 {}^{2} - (x + y) {}^{2} \\ 1 - (x + y)...1 + (x + y)$