Question

1+m2)x2+2mncx+(c2-a2)=0 has equal roots, prove that c2=a2(1+m2)

Answer 1

Answer:b²-4ac =0 if roots are equal.

Step-by-step explanation:b²-4ac=0

A=(1+m²)n²;B=2mnc;C=(c²-a²)

4m²n²c²-4[(1+m²)n²×(c²-a²)]=0

m²n²c²-n²c²+a²n²-m²n²c²+m²n²a²=0

-n²c²+a²n²+m²n²a²=0

n²(a²-c²+m²a²)=0

a²-c²+m²a²=0

c²=a²(1+m²)

Hence proved

Answer 2

Answer:

In the attachment.. Hope it's helpful..