Question

1. Magnetic field at centre of a long solenoid is Bo.
If length of the solenoid is increased by 60% and
number of turns also increased by 200%, then
magnetic field at centre of solenoid will be
(assume same electric current is supplied in each
case)​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

The magnetic field at the center of the solenoid will be 1.875B₀.

Explanation:

The magnetic field at the center of the solenoid is given as,

$B_0=\frac{\mu_0 NI}{l}$       (1)

Where,

B₀=magnetic field at the center of the solenoid

N=number of turns of the coil

I=current flowing through the solenoid

l=length of the solenoid

From the question we have,

The length is increased by 60% so,

$l'=(1+0.6)l=1.6l$      (2)

The number of turns is increased by 200% so,

$N'=(1+2)N=3N$      (3)

The new magnetic field at the center of the solenoid is given as,

$B=\frac{\mu_0 \times 3N\times I}{1.6l}$

$B=1.875\times \frac{\mu_0 \times N\times I}{l}$     (4)

By comparing equation (4) with equation (1) we get;

$B=1.875B_0$

Hence, the magnetic field at the center of the solenoid will be 1.875B₀.

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