(1)Magnetic force acts on a charged particle projected perpendicular to magnetic field is proportional to v^n........ where v=speed of particle. Find n.
(2)Magnetic force acts on a charged particle projected perpendicular to magnetic field is proportional to r^n......,.where r=radius of circular path. Find n.
Plzzzz explain using formulas involved and with correct explanation....!!!!
meenakshi997sa:
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Answers
Answered by
41
(2) For a particle moving in a plane perpendicular to external magnetic field we know that:
F = qvBsinθ = mv^2/r
or
F = mv^2r^-1
thus,
r^n = r^-1
or
n = -1
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OR
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When a charge particle is projected with velocity v perpendicular to the magnetic field,B, the force due to field is
F = q(vXB), where q is charge of particle. This force is perpendicular to B and v. This fact shows that the particle is moving on circular path in the field. In this situation the magnetic force provides the centripetal force necessary for circular motion. Therefore ,
mv^2/r=qvB.
If we stop here, then n=-1. But, if we write mv^2/r=mrw^2, then n =1.
F = qvBsinθ = mv^2/r
or
F = mv^2r^-1
thus,
r^n = r^-1
or
n = -1
-------
OR
-------
When a charge particle is projected with velocity v perpendicular to the magnetic field,B, the force due to field is
F = q(vXB), where q is charge of particle. This force is perpendicular to B and v. This fact shows that the particle is moving on circular path in the field. In this situation the magnetic force provides the centripetal force necessary for circular motion. Therefore ,
mv^2/r=qvB.
If we stop here, then n=-1. But, if we write mv^2/r=mrw^2, then n =1.
but the answer given is n=1
hmm
when we take v/r = omega.. then it is coming n= -1...... but if both the options are there what we will select?
but how to differentiate.. i mean if it is mcq then which option will we mark???
Answered by
1
Answer:
1) charge is proportional to v^n and v is speed then n=1
2) charge is proportional to r^n and r is the radius then also n=1
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