(1) Mark four numbers forming a square in a calendar.Add the squares of the diagonal pair and find the difference of these.Do this for other four numbers. Explain using algebra, why the difference is 14 always.
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We are going to find prime factors of 1575
1575=3×525
=3×3×175
=3×3×5×35
=3×3×5×5×7
Now, we are going to make a group of equal number.
=(3×3)×(5×5)×7
By observation, 7 prime factor is left out.
So, divide by 7 we get,
1575÷7= (3×3)×(5×5)
=(3×5)×(3×5)
=(15)×(15)
⇒ 225=(15)2
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