Question

(1 mark) question for 5 points

Find the ratio of AP and PB.

Please solve step by step...​

Answer 1

let common ratio=x

Therefore, PQ=x

and, BC=3x

Here, PQ is parallel to BC

Therefore, angle APQ= angleABC (corresponding angles )

similarily, angleAQP =angleACB

Therefore, Triangle APQ is similar to Triangle ABC

So by ratio theoram

Area of APQ/Area of ABC = (PQ/BC)^2 =(AP/AB)^2

From above

(AP/AB)^2= x^2/9x^2

(AP/AB)^2=1/9

And hence

AP/AB = 1/3

or 1:3

Here we get AP/AB = 1/3
Now Bo doing reciprocal on both sides we get

AB/AP = 3/1
subtracting 1 from both sides we get,

AB/AP -1 = 3/1 -1
Taking LCM

(AB-AP)/AP =2/1
PB/AP =2/1
Doing reciprocal again

AP/PB = 1/2



Hope its right if yes mark it as brainliest

Answer 2

Answer:

AP /PB =1/2

follow me...