Question

1 MARK QUESTIONS
1. In the given figure, AD and CE are medians of triangle ABC. DF is drawn parallel to CE.
Prove that
(i) EF = FB
(ii) AG : GD = 2 : 1
E
F
B
D
С​

Answer 1

Answer:

( (i) In ΔBFD and ΔBEC, ∠BFD = ∠BEC (Corresponding angles) ∠FBD = ∠EBC (Common) ΔBFD ~ ΔBEC (AA Similarity) (ii) In ΔAFD, EG || FD. Using Basic Proportionality theorem