Question

1. Match the following.
a) p (x) = x2 - 5x + 6 has
b) p (x) = x2 - 6x +9 has
c) p(x) = x2 - 2x + 3 has
( ) i) no zeros
( ) ii) Only one zero
( ) iii) two zeros
A) a -i, b - ii,c - iii
B) a - iii, b - ii, c-i
C) a - ii, b - iii, c-i
D) a - ii, b-i,c - iii​

Answer 1

Answer:

(B)

Step-by-step explanation:

a)

p(x) = X2 -2x-3x +6

p(x) = (x-2)(x-3)

for finding zeros

p(x) = 0

x = 2,3

so it has two zeroes

a) - iii

b)

p(x) = (x-3)^2

since

x= 3,3

it has only one zero

b) ii

c)

p(x) = X2 - 2x +3

it does not have defined value

c) i

so (B)