1 math question for all MATHS
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Step-by-step explanation:
∆ABC &∆ABD both are right angled at C and A respectively.
In ∆ABC &∆ABD
angle B=angle A
angle C=angle C (common)
So, both are similar by AA-similiarity
BA/AC=BD/DC
Answered by
2
Step-by-step explanation:
∆ABC &∆ABD both are right angled at C and A respectively.
In ∆ABC &∆ABD
angle B=angle A
angle C=angle C (common)
So, both are similar by AA-similiarity
BA/AC=BD/
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