Math, asked by genius932, 11 months ago

1 math question for all MATHS

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Answered by vivekyadav5641
2

Answer:2


Step-by-step explanation:

∆ABC &∆ABD both are right angled at C and A respectively.

In ∆ABC &∆ABD

angle B=angle A

angle C=angle C (common)

So, both are similar by AA-similiarity

BA/AC=BD/DC


Answered by LILPUMP12
2

Step-by-step explanation:

∆ABC &∆ABD both are right angled at C and A respectively.

In ∆ABC &∆ABD

angle B=angle A

angle C=angle C (common)

So, both are similar by AA-similiarity

BA/AC=BD/

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