Math, asked by manireddy32, 9 months ago

1 MB together can finish a piece of work of in 12 days if a alone can finish the same work in 20 days in how many days b alone can finish it​

Answers

Answered by sreerajpatnaik
0

Answer:

a can do work in 20 days

total work of a = 20 days

=1×20 days

then the fraction or part of work done by a in 1 day is 1/20

same like that..

total work done by both is in 12 days

1 day they can complete 1/12 th work

so b 1 day work =ab 1 day work-a i day work

=1/12-1/20

=2/60=1/30

b 1 day work =1/30

then b total work =30 days

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