Question

1. Measures of angles of □ABCD are in the ratio 4:5:7:8. Show that ABCD is a trapezium.

Solution : Let measures of A, B, C and D be (4x)º: (5x)"; (7x)" (8x)"
4x + 5x + 7x + 8x =___
sum of all angles of a quades lateral
X=__
A= B = 75°; Ç = __ _D = 120°
B+ A not equal 180°
side__Il side__
:. □ ABCD is a trapezium​

please help

Answer 1

Answer:

Let the ratio be x so angles of ABCD are

2x, 4x, 5x and 7x.

sum of angles in a quadrilateral is 360°.

2x + 4x + 5x + 7x = 360°

18x = 360°

x = 20o

So, the angles are A = 40°, B = 80°, C = 100°and D = 140°

A + D = 40° + 140° = 180°

B + C = 80° + 100° = 180°

So, ABCD is a trapezium with AB parallel to CD.