1 meter long massless string fixed with a wall is pulled horizontally by applying force of magnitude 10N calculate tension at point .5m away from wall
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16
For massless string, tension is same at all points
as force applied on both sides in 10 Newtons,
Tension=10 Newtons
as force applied on both sides in 10 Newtons,
Tension=10 Newtons
Answered by
12
Answer:
The tension will be 10 N.
Explanation:
Given that,
Length of string = 1 m
Force f = 10 N
We need to calculate the tension at point 5 m away from wall
According to newton's third law,
When one object apply a force on another object then the another object apply equal and opposite force on a first object.
So, The tension will be same at all points on the string.
The string is pulled by the 10 N force then the tension at the point 5 m away from the wall will be 10 N.
Hence, The tension will be 10 N.
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