Question

1 mg of uranium—235 is completely destroyed in an atomic bomb.how much energy is liberated?

Answer 1

Let me help you with this query.
We have to calculate the amount of energy released when 1 mg of uranium-235 is completely destroyed in an atomic bomb.
Solution:
From Einstein's Theory of Relativity, energy is equal to the product of mass and square of light speed.
i-e, E = mc²   ....... (1)
Which expresses that energy and mass are the physical quantities which can be changed into each other.
Now, given that 
Mass of Uranium = m = 1 g = 10⁻⁶ kg
Speed of light = c = 3 x 10⁸
Put these values in equation (1), we get:
E = mc²
E = (10⁻⁶) (3 x 10⁸)²
E = 9 x 10¹⁰ J
which is the required answer.
Hence 9 x 10¹⁰ J of energy is liberated when 1 mg of uranium-235 is completely destroyed in an atomic bomb.
Hope it will help you. Thanks.

Answer 2

Answer:

Explanation:1 mg of uranium is completely destroyed in an atomic bomb. How much energy is liberated?

What is the smartest way for transferring heavy data?

1 atom fission give 200Mev

If we consider energy only due to U235 bcoz it is a fissile material so

1gram ={6.023×10^23÷(235)}atoms

1 mgram ={above calculation ÷1000}atoms

Total energy in 1mg=200×1.6×10^-19×10^6× 1mg atoms

82.08 MJ (mega joule)

In atom bomb we take highly enriched material means max part of that material is U235

Other material used in atom bomb is pu239 so if we take 239 in place of 235 in above calculation you can get energy for pu239 hope you can understand.