1. Millikan performed an experiment method to determine
which of the following?
(a) Mass of the electron (b) Charge of the electron
(c) e/m ratio of electron (d) Both (a) and (b)
Answers
Answer:
Charge of the electron
Explanation:
because electron is a electricle method
Answer:
Robert Millikan and Harvey Fletcher conducted Millikan's oil drop experiment in 1909 to determine an electron's charge. They were able to suspend microscopic charged oil droplets between two metal electrodes by balancing the effects of gravity downward, drag up, and electric forces.
Explanation:
The charge of an electron was determined via Millikan's oil drop experiment.
Any electric charge in an electric field is subject to a force equal to the product of the charge and the electric field.
By measuring the amount of electric force and the size of the electric field on the tiny charge of a solitary oil droplet, Millikan was able to determine the charge's magnitude.
Millikan and Fletcher were able to determine the masses of the droplets based on their measured radii since the density of the oil was known (since from the radii they could calculate the volume and mass). Using the known electric field, the numbers for gravity and mass, and the charge on oil droplets in mechanical equilibrium, Millikan, and Fletcher determined the charge.
They repeated the experiment to show that all of the charges were multiples of a fundamental value.
They came up with a figure of 1.5924 * 10⁻¹⁹ Coulombs (C), which is within 1% of the number now accepted as being 1.602176487 * 10⁻¹⁹ C. They believed that this represented the charge of a single electron.
Hence, the correct option is (b) the charge of the electron.
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