Question

1 million atom of silver weight 1.79*10^(-16) g .calculate the atomic mass of silver

Answer 1

hey here is your answer
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$mole = \frac{no. \: of \: atoms}{avogadro \: no.(6.022 \times {10}^{23} )}$

given no. of silver atoms = 1 million = 10^6
$now. \\ mole = \frac{ {10}^{6} }{6.022 \times {10}^{23} }$
we also know that
$mole = \frac{given \: mass \: of \: element}{atomic \: mass \: of \: element} \\ \\let \: the \: atomic \: mass \: of \: silver \: be \: x \\ \\ \frac{ {10}^{6} }{6.022 \times {10}^{23} } = \frac{1.79 \times {10}^{ - 16} }{x} \\ \\ x = \frac{1.79 \times {10}^{ - 16} \times 6.022 \times {10}^{23} }{ {10}^{6} } \\ \\ x = 1.79 \times 6.022 \times {10}^{ - 16 + 23 - 6} \\ \\ x = 10.77938 \times {10}^{1} \\ \\ x = 107.7938 \: gram$
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Answer 2

Answer:

107.7938g is the atomic mass of silver