1 minus cos theta divided by 1 plus cis theta
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Answer:
Step-by-step explanation:
1 - Cosθ/1 + Cosθ
=> 1 - Cos2(θ/2) / 1 + Cos2(θ/2)
We know that Cos2θ = 1 - 2Sin²θ = 2Cos²θ - 1
=> 1 - (2Cos²θ/2 -1)/ 1 + (2Cos²θ/2 -1)
= 1 + 1 - 2Cos²θ/2 / 2Cos²θ/2
= 2 ( 1 - Cos²θ/2)/2Cos²θ/2
= Sin²θ/2/Cos²θ/2
= Tan²θ/2.
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