1 ml of .1 MHCl is added into 99 ml of water. Assume volumes are additive, what is pH of resulting solution.
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You need to find the molarity now after diluting , Its easy because moles of HCl remain the same , so equate them ,
1*1=100*M
M= new molar conc.
On solving and taking -log[H] , we get 2 while earlier it was 0
Hence change should be 2
ashupushkar38:
hii
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ur answer is 2 ........hope it helps..
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