1 mol of CO2 contains
(a) 3 gram atoms
(b) 6 × 10^23 atoms
(c) 6 × 10^23 atoms of C
(d) 18 × 10^23 molecules of CO2
(e) Both (a) and (c)
Please answer with a explanation.
Answers
Answered by
13
hey there
correct option is (e)
3 gram of atoms and 6*10^23 atoms of C
we have2 mol. of CO2
so, 2*6.022*10^23
= 1.2044*10^23
now 1 mol. of CO2 contains 3 atoms
1 of carbon and 2 of oxygen
so, no. of atoms in 2 mol. of CO2
=3* 1.2044*10^23
= 3.6132* 10^24
molecule of carbons present in CO2
= 1* 6.022*10^23
= 6.022*10^23
plss mark as brainliest
correct option is (e)
3 gram of atoms and 6*10^23 atoms of C
we have2 mol. of CO2
so, 2*6.022*10^23
= 1.2044*10^23
now 1 mol. of CO2 contains 3 atoms
1 of carbon and 2 of oxygen
so, no. of atoms in 2 mol. of CO2
=3* 1.2044*10^23
= 3.6132* 10^24
molecule of carbons present in CO2
= 1* 6.022*10^23
= 6.022*10^23
plss mark as brainliest
alishan20102:
please tell how to get the answer
Answered by
5
Answer:
correct answer is option (e)
Explanation:
option a is correct because there is 1 gram molecule that contains 3 gram atoms
no of atoms in a molecule = molecularity x no of mole of molecules
= 3 x 1
= 3
option c is also correct because
1 molecule of co2 contains 1 carbon atom
so 1 mole of co2 contain 1 mole of carbon atom i.e 6 x 10^23
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