Question

1 mol of ideal gas at temperature T1 expands slowly according to the law of p/v= constant . its final Temperature is T2 . the work done by the gas is ?​

Answer 1

The work done by the gas is W = R / 2 (T2−T1).

Explanation:

Given data:

Number of moles of gas = 1 mole

Work done "W" = ∫V2 - V1 PdV

                          = ∫V2 - V1 KVdV

(Since pV=  constant)

W = 1 / 2 k(V2^2 − V1^2)

PV = RT

But p = KV

KV^2 = RT

K(V2^2−V1^2) = R(T2−T1)  

W = R / 2 (T2−T1)

Thus the work done by the gas is W = R / 2 (T2−T1).

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