Question

1 mol of ideal gas expand reversibly and isothermally to
double its volume at 300 K. The work done during the
process is approximately (in L atm)
A.O -8.9
B.O -17.1
C.O -28.5
D.O -42.0​

Answer 1

Answer:

1 mol of ideal gas expand reversibly and isothermally to

double its volume at 300 K. The work done during the

process is approximately (in L atm)

answer

C.O -28.5

Answer 2

Given:

Ideal gas of one Mole expanding isothermally and reversibly to

double its initial volume at 300 $K$.

To Find:

W =Work get done during process of expansion reversibly and isothermally  = ?

Solution:

Work get done for isothermally and reversible expansion process by gas

$W = -2.303nRT\dfrac{log(V_{2} )}{log(V_{1}) }$

$n$ = no of mole = 1

$R$ = Gas constant = 0.0821 $L atm /mole K$

T = Temperature = 300 $K$

$V_{2}$ is double of its Volume $V_{1}$

$W = -2.303*1*0.0821*300\dfrac{log(2)}{log(1) }$

$W = -56.72\ddfrac{log(2) }$

$log 2= 0.3$

$W = -17.01$ $L atm$

B is the correct option of this question