1 mol of iron reacts completely with 0.65 mol o2
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2Fea mole+O2a2mole→2FeOa 4Feb+3O23b4→2Fe2O3b2 ∴a+b=1 a 2+3b4=0.65 ∴a=0.4 mole b=0.6 mole ∴ moles of FeO=0.4 moles of Fe2O3=0.3
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