Question

1 mol of n2 and 4 mol of h2 are allowed to react in a vessel to form nh3 gas as only product and after reaction, water is added. Aqueous solution required 1 mol of hcl for complete reaction. Mol fraction of h2 in the gas mixture after reaction is

Answer 1

Mole fraction of H2 in the gas mixture after reaction is 5/6.

Explanation:

• Only 1 mole of NH3 gas is formed

 Solution requires 1 mole of HCl and hence only 1 mole of NH3 is required.

 HCl     +     NH3     ----->   NH4Cl

1 mole       1 mole

• For NH3 formation:

                       N2 +       3 H2 ------->      2 NH3

Initial moles    1 .          4.                         0

Final mole      1-x          4 -3x                    2x

2x = 1

 Hence x = 0.5

 Mole fraction of H2 gas in final mixture

 = 2.5 /(0.5 + 2.5) = 2.5 /3 = 5/6

Hence mole fraction of H2 in the gas mixture after reaction is 5/6.

Also learn more

In aqueous solution of H2SO4 the mole fraction of water is 0.85 .the molality of solution is?

https://brainly.in/question/3838204

Answer 2

Answer:

this is your questions answer