Question

1 mol zn+2कोzn में अपचयित करने के लिए कितने आवेश की आवश्यकता होगी?​

Answer 1

Answer: The charge required for 1 mole of $Zn^{2+}$ will be, 193000 C

Explanation:

As we know that if 'n' electrons are involved in the reaction, then the charge required for the reaction of 1 mole of substance by (n × Faraday).

1 Faraday = 96500 C

The half-balanced reduction reaction will be,

$Zn^{2+}+2e^-\rightarrow Zn$

From the balanced chemical reaction, we conclude that

The number of electrons (n) in the reaction are 2.

The quantity of charge required for the reduction of 1 mole of $Zn^{2+}$ = $2\times F=2\times 96500C=193000C$

Hence, the charge required for 1 mole of $Zn^{2+}$ will be, 1,93,000 C