1 molar glucose and 1 molar nacl and 1 molar cacl2 which has higher freezing point
Answers
Answered by
1
It happens because, elevation in boiling point is taken as
ΔTb = Kb x m x i
Where, Kb = molal elevation constant of solvent, i = Vant Hoff factor, m = molality
Now, as solvent is water so Kb = constant for both and
Molarity of urea= molarity of glucose = 1M = 1moles/1L of water
So, molality = moles/ Kg solvent = 1( for water 1L = 1Kg)
Here, as glucose and urea both of them are not ionic so i = 1 for both
Thus for both the compounds,
ΔTb = Kb x m x i = Kb x1x 1 = Constant
Hence, the answer says that both are same.
ΔTb = Kb x m x i
Where, Kb = molal elevation constant of solvent, i = Vant Hoff factor, m = molality
Now, as solvent is water so Kb = constant for both and
Molarity of urea= molarity of glucose = 1M = 1moles/1L of water
So, molality = moles/ Kg solvent = 1( for water 1L = 1Kg)
Here, as glucose and urea both of them are not ionic so i = 1 for both
Thus for both the compounds,
ΔTb = Kb x m x i = Kb x1x 1 = Constant
Hence, the answer says that both are same.
Similar questions