Question

1 molar mixture of He and

CH4

is containing in a

vessel at 20 bar pressure. Due to a hole in the

vessel, the gas mixture leaks out, what is the

composition of the mixture effusing out initially?​

Answer 1

Answer:

M(CH4)= 16M(He)= 4

Let total pressure=P

Then, P(he) = (4/5)P & P(CH4) = (1/5)P

Now r(He)/r(CH4) = [P(He)/P(CH4)]× √[M(CH4)/M(He)]

ANS : r(he)/r(CH4) = 8:1

it's an nice ans am I right?